Class 9th (SA-II) MATHEMATICS Assignment-2011for FA-3

JSUNIL TUTORIAL,SAMASTIPUR

Class 9^th (SA-II)

^{MATHEMATICS Assignment-I (For month of November)}     

Q1.  Determine the point on the graph of the linear equation x+y=6, whose ordinate is twice its abscissa.

Q2.  How many solution(s) of the equation 3x+2=2x-3 are there on the

          i) Number Line            ii) Cartesian plane

Q3.  Draw the graph of the equation represented by the straight line which is parallel to the x-axis and 3 units above it.

Q4. Find the solutions of the linear equation x+2y=8, which represents a point on

           i) x axis                            ii) y-axis

Q5.  For what values of c, the linear equation 2x+cy=8 has equal values of x and y as its solution.

Q6. Give the geometrical interpretations of 5x+3=3x-7 as an equation

           i) in one variable              ii) In two variables

Q7. Draw the graph of the equation 3x+4y=6. At what points, the graph cut the x-axis and the y-axis.

Q8. At what point does the graph of equation 2x+3y=9 meet a line which is parallel to y -axis at a distance 4 units from the origin and on the right side of the y-axis.

Q9.  P is the mid point of side BC of parallelogram ABCD such that AP bisects angle A.

Prove that AD =2CD.

Q10. Prove that bisector of any two consecutive angles of parallelogram intersect at right angles.

Q11. E and F are respectively the midpoints of non parallel sides AD and BC of trapezium. Prove that EF is parallel to AB and EF=1/2(AB+CD).

Q12.  ABCD is a rectangle in which diagonal BD bisects angle B. Show that ABCD is a Square.

Q13.  Diagonals of Quadrilateral ABCD bisect each other. If angle A = 35 degree, determine angle B.

Q14. The bisectors of angle B and angle D of quadrilateral ABCD meet CD and AB, produced at point P and Q respectively. Prove that angle P+angle Q= ½(angle ABC+ angle ADC).

Q15. In parallelogram ABCD, AB=10cm, AD= 6cm. The bisector of angle A meets DC in A. AE and BC produced meet at F. Find the length of CF.

Q16. Evaluate: (5x+1) (x+3)-8= 5(x+1) (x+2).